2(x^2)-8x+10=0

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Solution for 2(x^2)-8x+10=0 equation: 



2(x^2)-8x+10=0

a = 2; b = -8; c = +10;
Δ = b2-4ac
Δ = -82-4·2·10
Δ = -16
Delta is less than zero, so there is no solution for the equation

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